Explanation:
(a) n² + 3
First term = 1² + 3 = 4
Second term = 2² + 3 = 7
Third term = 3² + 3 = 12
Fourth term = 4² + 3 = 19
10th term = 10² + 3 = 103
(b) 2n²
First term = 2(1)² = 2
Second term = 2(2)² = 8
Third term = 2(3)² = 18
Fourth term = 2(4)²= 32
10th term = 2(10)² = 200
Hence, this is the required solution.