Question

The vertices of a triangle are a(3,root3), b(3,-root3) and c(0,0).find its perimeter.

Answer 1

We need to find the lengths of ab, bc and ca then add them up.

ab = sqrt ( -root3 ^2 + 3^2) = sqrt 12

bc = sqrt ( 3^2 -0^2 + (-root3)^2- 0^2) = sqrt 12

ca = sqrt ( 3^2 + root3^2) = sqrt 12

So the Perimeter = 3 sqrt 12 = 3 * 2 * sqrt3 = 6 sqrt3 ANSWER