Question

Someone help me on this one pls!!

Answer 1

The formula of a midpoint of AB:

`M_(AB)\left((x_A+x_B)/(2);\ (y_A+y_B)/(2)\right)`

We have:

G(b; 0); F(3b; 2b)

substitute:

`M_(GF)\left((b+3b)/(2);\ (0+2b)/(2)\right)\to M_(GF)(2b;\ b)`

Answer: (2b, b)