Question

the admission fee at the amusement park is $3.00 for children and 6.40 fo adults on a certain day 275 people entered the park and the admission fees collected totaled $1284 how many children and adults were admitted

Answer 1

Let the variables be c and a.

c+a = 275 (people)

($3/child)(c) + ($6.40/adult)(a) = $1284

Solve c+a = 275 for c and subst. the result into the other equation, to eliminate the variable c:

c = 275-a

Then 3(275-a) +6.40(a) = 1284, or 825 - 3a + 6.40a = 1284

Combining like terms: 9.40a = 459. Then, a = 459/9.40 = 48.83

This makes no sense. I've checked these calculations for errors twice. Would you please go back and ensure that you have copied down the original problem completely and accurately? Thanks.

combining like terms, we get 459 = 9.40a. Solving for a: a = 459/9.40 =

Answer 2

Children=x
Adults=y
* x + y =275 => x = 275 - y
* 3.00x + 6.40y = 1284 <=> 3.00(275 - y) + 6.40y = 1284 <=> ... <=> y = 135 => x = 275 - 135 = 140
Children: 140
Adults: 135