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3 votes
I’m confused on this one

I’m confused on this one-example-1
User Neerkoli
by
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2 Answers

2 votes

The answer is




First of all, note that we can solve all angles, since we have



\hat{A}+\hat{B}+\hat{C} = 180 \iff \hat{A}+90+44.25 = 180 \iff \hat{A} = 180-90-44.25 = 45.75


where
\hat{A} is the angle centered in vertex A, and so on.


Now we can use the law of sines, which states that the ratio between a side and the sine of the opposite angles is constant.


So, you would have



\frac{AC}{\sin(\hat{B})} = \frac{BC}{\sin(\hat{A})}


plug in the known values:



(8.6)/(\sin(90)) = (BC)/(\sin(45.75))


Since sin(90)=1, the denominator of the first fraction disappears. Finally, we can solve for BC:



BC = 8.6 \cdot \sin(45.75) \approx 8.4338\ldots


Which gives 8.43 when rounded as required.


User Santosh Karanam
by
8.4k points
4 votes
Y would equal 6.16.

We can use trigonometry and label AC as the hypotenuse and BC as the adjacent side.

This means we have to use the cosine ratio, cos = Adjacent/hypotenuse, and so to find the adjacent we must do cos(44.25) × 8.6, which is 6.16.

I hope this helps!
User Arora
by
7.7k points

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