Part A
Each year the number of alligators is 1.25 times the number the year before. Repeated multiplication by this value can be represented using an exponent. The equation for the number of alligators (a) as a function of the number of years (t) can be written as
... a(t) = 20·1.25^t
Each year, the number of crocodiles increases by 10. Repeated addition can be represented using multiplication. The equation for the number of crocodiles (c) as a function of the number of years (t) can be written as
... c(t) = 25 +10t
Part B
... a(4) = 20·1.25⁴ ≈ 48.83 ≈ 49
... c(4) = 25 +10·4 = 65
After 4 years, there are 49 alligators and 65 crocodiles.
Part C
You want t that solves a(t) = c(t). Such an equation cannot be solved algebraically, but it can be solved by any of a variety of other methods. My personal preference is for a graphical solution.
After approximately 7 years, the number of animals of each type will be the same, 95.
a(7) = 95.4
c(7) = 95
These numbers both round to 95.