Answer:
See explanation
Step-by-step explanation:
Let the rate of diffusion of the unknown gas be x
Let the rate of diffusion of nitrogen be y
Let molecular mass of unknown gas be MX
Let molecular mass of nitrogen be My
Hence;
x/y = √My/MX
0.936/1 = √28/MX
(0.936/1)^2= 28/MX
MX= 28/0.876096
MX= 32 g/mol
MX is O2 gas