Question

A rock is thrown at an angle such that the initial horizontal velocity is

15.0 m/s and the initial vertical velocity is 39.0 m/s. What is the greatest height the rock reaches?


A.38.8 m
B.46.9 m
C.77.6 m
D.98.2 m

Answer 1

Option (c) is correct.

Step-by-step explanation:

initial velocity along horizontal= Vx=15 m/s

initial velocity along vertical= Viy=39 m/s

final vertical velocity at the top= 0

acceleration due to gravity=-9.8 m/s²

using kinematic equation

Vfy²= viy²+2gh

0=(39)²+2 (-9.8) (h)

-1521=-19.6 h

h=77.6 m