163k views
1 vote
CAN SOMEONE HELP ME . SIDE NOTE: HAVE MORE QUESTIONS SO IF SOMEONE GOOD AT THIS SUBJECT CAN HELP THROUGH EMAIL I CAN GIVE YOU THE POINTS

CAN SOMEONE HELP ME . SIDE NOTE: HAVE MORE QUESTIONS SO IF SOMEONE GOOD AT THIS SUBJECT-example-1
User Hojoon
by
8.0k points

1 Answer

4 votes

Remark

I take it this is your most recent question. If not, put a link to the question you'd like answered.


You have to use the law of sines to solve this. I know of no other way.


Step One

Find the third angle.

All triangles have 180 degrees. There is no exception to this rule. You cannot find a triangle that would measure A = 60 B = 60 and C = 79. It cannot be constructed. So what's the third angle? Call it x


x + 12 + 150 = 180 combine the left side

x + 162= 180 subtract 162

x = 180 - 162

x = 18


Step Two

Set up the Sine law that will solve for c



(c)/(Sin(18)) = (10)/(Sin(12))


Notice how the angles are sides of each ratio are opposite one another. Easy way to remember the sine law.


Step Three

Substitute values into the proportion

c/0.30902 = 10/0.2079


Step Four

Cross multiply and solve

0.2079 * c = 10 * 0.30902

0.2079 * c = 3.0902 Divide by 0.2079

c = 3.0902 / 0.20902

c = 14.863

User Sharad
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories