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The isotope carbon-14 decays over time into nitrogen-14 with a half-life of 5,730 years. Suppose that you find a fossil that contains 1.25 grams of carbon-14 and 3.75 grams of nitrogen-14. How old is the fossil

User Psparrow
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2 Answers

11 votes

Final answer:

To calculate the age of a fossil with 1.25 grams of carbon-14 and 3.75 grams of nitrogen-14, we determine that two half-lives of carbon-14 have passed, which equals approximately 11,460 years. Therefore, the fossil is around 11,460 years old.

Step-by-step explanation:

The question involves using the half-life of carbon-14 to determine the age of a fossil. The isotope carbon-14 decays into nitrogen-14, and by measuring the ratio of the two substances in the fossil, we can estimate how many half-lives have passed since the organism died. Given that the half-life of carbon-14 is approximately 5,730 years, and the fossil contains 1.25 grams of carbon-14 and 3.75 grams of nitrogen-14, we can infer that for every gram of carbon-14 that has decayed, a gram of nitrogen-14 has been formed.

Initially, there would have been 5 grams of carbon-14 and zero grams of nitrogen-14. After one half-life (5,730 years), half of the carbon-14 would have decayed, leaving us with 2.5 grams of carbon-14 and 2.5 grams of nitrogen-14. Since we now have 1.25 grams of carbon-14 remaining, another half-life has passed, meaning the total time elapsed is two half-lives or 11,460 years. Therefore, the fossil is approximately 11,460 years old.

User Clarius
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Answer:

11460 years

Step-by-step explanation:

0.693/t1/2 = 2.303/t log (No/N)

t1/2 = half life of the carbon

t = age of the fossil

No= amount of radioactive material originally present

N= amount of radioactive material present at time=t

No= mass of carbon + nitrogen = 5g

0.693/5730 = 2.303/t log (5/1.25)

1.21 ×10^-4 = 1.3866/t

t= 1.3866/1.21 ×10^-4

t= 11460 years

User Minna
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