268,258 views
39 votes
39 votes
30 POINTS

Write and solve an absolute value equation for the minimum and maximum times for an object moving at the given speed to travel the given distance. Absolute value 3 ft. 10 ft/s for 30 ft​

30 POINTS Write and solve an absolute value equation for the minimum and maximum times-example-1
User Viacheslav Kroilov
by
2.6k points

2 Answers

11 votes
11 votes

Answer:

Explanation:

12

User Yggdraa
by
3.0k points
22 votes
22 votes

The minimum and maximum time for the object to travel 30 feet at a speed of 10 ft/s is 3 seconds.

How to determine the minimum and maximum times

To determine the minimum and maximum times for an object to travel a distance of 30 feet at a speed of 10 ft/s, set up an absolute value equation.

Let's denote the time it takes for the object to travel the distance as t.

The distance traveled by the object is given by the formula:

Distance = Speed * Time

In this case, the distance is 30 feet, and the speed is 10 ft/s.

Thus, we have:

30 = 10t

To find the minimum and maximum times, consider the absolute value of the expression 10t.

The absolute value of a number represents its distance from zero on a number line, always resulting in a non-negative value.

Therefore, our absolute value equation becomes:

|10t| = 30

To solve this equation, we can split it into two cases:

Case 1: 10t = 30

Solving for t:

t = 3

Case 2: -(10t) = 30

Solving for t:

-10t = 30

Dividing by -10 (note that dividing by a negative number flips the inequality):

t = -3

However, since time cannot be negative in this context, we discard the second case.

Therefore, the minimum time for the object to travel 30 feet at a speed of 10 ft/s is 3 seconds.

User Mechelle
by
3.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.