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2x+3y=3 and -10x+2y=-32

User Vishalaksh
by
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1 Answer

2 votes

2x + 3y = 3

-10x + 2y = -32


Solve using the substitution method.

Solve for x in the first equation.


2x + 3y = 3

Subtract 3y from both sides.


2x = 3 - 3y

Divide both sides by 2.


x =
(3)/(2) -
(3)/(2)y

Plug x into the second equation.


-10(
(3)/(2) -
(3)/(2)y) + 2y = -32

Distribute -10 inside the parentheses.


-15 + 15y + 2y = -32

Combine like terms.


-15 + 17y = -32

Add 15 to both sides.


17y = -17

Divide both sides by 17.


y = -1

Plug y into the first equation.


2x + 3(-1) = 3

Multiply 3 by -1.


2x - 3 = 3

Add 3 to both sides.


2x = 6

Divide both sides by 2.


x = 3


x = 3;

y = -1

User Jose Paredes
by
5.5k points