Question

The specific heat capacity of water is 4.184 J/(g·ºC). How much thermal energy is required to change the temperature of 700.0 g of water from 25.6ºC to 75.4ºC?

Answer 1

145854.24J

Step-by-step explanation:

Given parameters:

Specific heat capacity of water = 4.184J/g°C

Mass of the water = 700g

Initial temperature = 25.6°C

Final temperature = 75.4°C

Unknown:

Thermal energy = ?

Solution:

To solve this problem, we use the expression below;

H = m x c x Ф

H is quantity of heat

m is the mass

c is the specific heat capacity

Ф is the temperature change

H = 700 x 4.184 x (75.4 - 25.6) = 145854.24J