Question

5 Four children all play a computer game on the first day of the year. Then Anne plays every second day, Bernard plays every third day, Charles plays every fourth day and Danielle only plays every fifth day. What is the date when they next all play on the same day? b On how many days of the year do they all play on the same day?

Answer 1

To find the date when all four children will play the game on the same day, find the least common multiple (LCM) of the numbers 2, 3, 4, and 5. To find how many days of the year they all play on the same day, divide the number of days in a year by the LCM. They will play on the same day 6 times in a year.

Step-by-step explanation:

To find the date when all four children will play the game on the same day, we need to find the least common multiple (LCM) of the numbers 2, 3, 4, and 5. The LCM of these numbers is 60. Therefore, the children will next all play on the same day after 60 days.

To find how many days of the year they all play on the same day, we need to find the number of multiples of 60 within a year. Since 60 is a common multiple of 2, 3, 4, and 5, they will play on the same day every 60 days. There are 365 days in a year, so they will play on the same day 365 ÷ 60 = 6 times.

Answer 2

ednesday (9 weeks later) = 10th October.
ep-by-step explanation:
e label the days with the initials of the
imes.
M= 4
D=7
B=6
LCM of 6 +7 = 42
LCM of 6+7 + 4 = 84
We find 84 is the amount of days we need
to add on to july 18th
We first find the weeks 84/7 = 9 weeks.
As Wednesday July 18th is exclusive it
would be 84 days after this event.
18+84 = 102 days.
31 days in july = 31
31 days in Aug = 31
30 days in Sept = 30
= 92
102-92 = 10
We now know date is Wednesday 10th
October
We can check 84 days = 9 weeks