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Sum in sigma notation and find the sum of each series
150+140+130+120+110+100

1 Answer

4 votes

we are given


150+140+130+120+110+100

first term is 150

so,


a_1=150

now, we can find common difference


d=140-150


d=-10

now, we can find nth term


a_n=a_1+(n-1)d


a_n=150+(n-1)*-10


a_n=-10n+160

we can see that

total number of terms is 6

so, we can write it in sigma form as


\sum _(n=1)^6\:\left(-10n+160\right)

now, we can find sum


sum=750.............Answer

User Shikhar Arora
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