Question

Select the two values of x that are roots of this equation x^2+3x-5=0

Answer 1

x = -(3-sqa(29))/2

x= -(3+sqa(29))/2

decimal form

x = 1.193, -4.1923

Answer 2

Answer : The two values of 'x' are, 1.192 and -4.192

Step-by-step explanation :

The given expression is,

`x^2+3x-5=0`

To solve this problem we are using quadratic formula.

The general quadratic equation is,

`ax^2+bx+c=0`

Formula used :

`x=(-b\pm √(b^2-4ac))/(2a)`

Now we a have to solve the above equation and we get the value of 'x'.

`x^2+3x-5=0`

a = 1, b = 3, c = -5

`x=(-b\pm √(b^2-4ac))/(2a)`

`x=(-(3)\pm √((3)^2-4* 1* (-5)))/(2* 1)`

`x=(-3+√((3)^2-4* 1* (-5)))/(2* 1)`

`x=1.192`

and,

`x=(-3-√((3)^2-4* 1* (-5)))/(2* 1)`

`x=-4.192`

Therefore, the values of 'x' are 1.192 and -4.192