Question

How many ml are in 1.25 l of a intravenous solution of 0.9% sodium chloride?

Answer 1

Mass % of NaCl = 0.9 % (m/v)

Density of 0.9 % NaCl is about 1.0 g/mL

Volume of NaCl in mL :

`1.25 L solution * (1000 mL)/(1 L) * (0.9 g NaCl)/(100 mL solution)*(1 mL)/(1.0 g NaCl)`

= 11.25 mL NaCl