2 Answers

Flawr · Answer 1 · 2019-09-17T11:01:17+0000

You're looking for the total surface of a cylinder, which is composed by two circles, and a rectangle conntecting them.

The area of the two circles is given by

$A = \pi r^2 = \pi 3^2 = 9\pi$

The base of the rectangle is congruent to the circumference of the base circle, and the height is given. The circumference is given by

$C = 2\pi r = 2\pi\cdot 3 = 6\pi$

So, the area of the rectangle is

$6\pi \cdot 11.5 = 69\pi$

The cylinder is consists of two circles and the rectangle, so its surface is

$69\pi +2\cdot 9\pi = 69\pi + 18\pi = 87\pi$

Ben Golden · Answer 2 · 2019-09-21T11:09:39+0000

Radius = Diameter ÷ 2

Radius = 6 ÷ 2 = 3cm

Surface area = 2πr² + 2πrh

Surface area = 2 π (3)² + 2 π (3) (11.5) = 272.32 cm² (nearest hundredth)

Answer: 272.32 cm²

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