Question

How many moles of NO2 are equivlent to 74.3 grams of NO2N=14.01/ o=16.00?

Answer 1

The molecular mass of
`HNO_2` is: 1·1 + 1·14.01 + 2·16 = 47.01 g/mol.

Now we can convert the mass into mol of
`HNO_2`:

`74.3\ g\ HNO_2\cdot (1\ mol)/(47\ g) = \bf 1,58\ mol\ HNO_2`