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The number of lightning strikes in a year at the top of a particular mountain has a poisson distribution with a mean of 3.8. find the probability that in a randomly selected year, the number of lightning strikes is 0.

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Let X be the number of lightning strikes in a year at the top of particular mountain.

X follows Poisson distribution with mean μ = 3.8

We have to find here the probability that in randomly selected year the number of lightning strikes is 0

The Poisson probability is given by,

P(X=k) =
(e^(-mean) mean^(x))/(x!)

Here we have X=0, mean =3.8

Hence probability that X=0 is given by

P(X=0) =
(e^(-3.8) 3.8^(0))/(0!)

P(X=0) =
(0.02237 * 1)/(1)

P(X=0) = 0.0224

The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224