Question

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.0.25 M0.44 M0.75 M4.0 M

Answer 1

0.25

Moles of solute = (Liters of solution) x (molarity of solution)

Moles of solute = (Kg of solution) x (molality of solution)

Answer 2

The molecular mass of
`H_2SO_4` is:

2·1 + 1·32 + 4·16 = 98 g/mol

The amount of solute, expressed by mol, is:

`73.5\ g\ H_2SO_4\cdot (1\ mol)/(98\ g) = 0.75\ mol\ H_2SO_4`

The molar concentration definition is:
`M = (mol\ solute)/(volume (L)\ solution)`

Doing the calculations:

`M = (0.75\ mol)/(3\ L) = \bf 0.25\ M`

(If you detect any mistakes in my English report me them, please).