Question

Rebekah kicks a soccer ball off the ground and in the air, with an initial velocity of 25 feet per second. Using the formula H(t) = −16t^2 + vt + s, what is the maximum height the soccer ball reaches?9.5 feet9.8 feet10.2 feet10.7 feet

Answer 1

Your answer would be, Letter Choice, (B), 9.8 Ft.

hope that helps!!!! : )

Answer 2

Maximum height, H(t) = 9.8 feet

Explanation:

It is given that, Rebekah kicks a soccer ball off the ground and in the air.

Initial velocity of the ball, v = 25 feet per second

The height as a function of time is given by :

`H(t)=-16t^2+vt+s`................(1)

s = 0

For maximum height,
`(dH(t))/(dt)=0`

`(d(-16t^2+25t))/(dt)=0`

-32 t + 25 = 0

t = 0.78 s

The maximum height of the soccer ball can be calculated using the value of t in equation (1) as :

`H(t)=-16(0.78)^2+25* 0.78`

H(t) = 9.76 feet

or

H(t) = 9.8 feet

So, the maximum height the soccer ball reaches is 9.8 feet. Hence, the correct option is (b).