The Pyhtagorean triple for a 45-45-90 is
![(x,x,x√(2))](https://img.qammunity.org/2019/formulas/mathematics/high-school/in85aii1a1qxkfjw80gg163hqpecdu3wdm.png)
with the last measure being that of the hypotenuse since it is the longest. If the hypotenuse is given as
![22√(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/bqy6x1gbh4owulnj918x1bepd4gtr2zc91.png)
then in equality form we could rewrite as
. We would divide both sides by the square root of 2 and solve for x, the length of each leg of that triangle. Each leg measures 22.