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Given tan of theta = -2 and pi/2; find cos(2theta)

2 Answers

2 votes

Answer:

[D] cos2θ = - 3/5

User Janosdivenyi
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Given tan of theta = -2 and pi/2; find cos(2theta)
The identity of cos (2 theta)=
cos(2\theta )=(1-tan^2\theta )/(1+tan^2\theta )
Given tan of theta = -2 and pi/2.
So, let's plug in tan theta= -2

cos(2\theta)= (1-(-2)^2)/(1+(-2)^2)
=
(1-4)/(1+4) (Squaring)
=
(-3)/(5) (simplifying)
So, cos ( 2 theta) = -3/5.
Now we can plug in tan theta = π/2

cos(2\theta)= (1-(π/2)^2)/(1+(π/2)^2)
=
(1-pi^2/4)/(1+pi^2/4) (Squaring)
=
(4-pi^2)/(4+pi^2) Simplifying
So, cos ( 2 theta)= -3/5 and (4-pi^2)/(4+pi^2)

User Relidon
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