117k views
2 votes
Solve the system by using the technique of ‘elimination’: -2x+5y=-42,7x+2y=30

User Sterlin
by
4.9k points

1 Answer

5 votes

Solve the following system using elimination:

{5 y - 2 x = -42 | (equation 1)

7 x + 2 y = 30 | (equation 2)

Swap equation 1 with equation 2:

{7 x + 2 y = 30 | (equation 1)

-(2 x) + 5 y = -42 | (equation 2)

Add 2/7 × (equation 1) to equation 2:

{7 x + 2 y = 30 | (equation 1)

0 x+(39 y)/7 = (-234)/7 | (equation 2)

Multiply equation 2 by 7/39:

{7 x + 2 y = 30 | (equation 1)

0 x+y = -6 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{7 x+0 y = 42 | (equation 1)

0 x+y = -6 | (equation 2)

Divide equation 1 by 7:

{x+0 y = 6 | (equation 1)

0 x+y = -6 | (equation 2)

Collect results:

Answer: {x = 6, y = -6

User Dusz
by
4.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.