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6x+2(x+4)<2x+20 solve for inequality

User Rashae
by
7.1k points

1 Answer

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The problem to solve is:

6x+2(x+4)‹2x+20

First, let's work on the left hand side of your inequality, the 6x+2(x+4)

This means, for instance, to see if it can be simplified at all.

Multiply x and 6

Multiply x and 1

The x just gets copied along.

The answer is x

x

6*x evaluates to 6x

x+4 evaluates to x+4

Multiply 2 by x+4

we multiply 2 by each term in x+4 term by term.

This is the distributive property of multiplication.

Multiply 2 and x

Multiply 1 and x

The x just gets copied along.

x

2 × x = 2x

Multiply 2 and 4

1

2 × 4 = 8

2*(x+4) evaluates to 2x+8

6x + 2x = 8x

The answer is 8x+8

6*x+2*(x+4) evaluates to 8x+8

So, all-in-all, the left hand side of your inequality can be written as: 8x+8

Now, let's work on the right hand side of your inequality, the 2x+20

Multiply x and 2

Multiply x and 1

The x just gets copied along.

The answer is x

x

2*x evaluates to 2x

2*x+20 evaluates to 2x+20

The right hand side of your inequality can be written as: 2x+20

So with these (any) simplifications, the inequality we'll set out to solve is:

8x+8 ‹ 2x+20

Move the 8 to the right hand side by subtracting 8 from both sides, like this:

From the left hand side:

8 - 8 = 0

The answer is 8x

From the right hand side:

20 - 8 = 12

The answer is 12+2x

Now, the inequality reads:

8x ‹ 12+2x

Move the 2x to the left hand side by subtracting 2x from both sides, like this:

From the left hand side:

8x - 2x = 6x

The answer is 6x

From the right hand side:

2x - 2x = 0

The answer is 12

Now, the inequality reads:

6x ‹ 12

To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)

around the x on the left side of the inequality.

The last step is to divide both sides of the inequality by 6 like this:

To divide x by 1

The x just gets copied along in the numerator.

The answer is x

6x ÷ 6 = x

12 ÷ 6 = 2

The solution to your inequality is:

x ‹ 2

So, your solution is:

x must be less than 2The problem to solve is:

6x+2(x+4)‹2x+20

First, let's work on the left hand side of your inequality, the 6x+2(x+4)

This means, for instance, to see if it can be simplified at all.

Multiply x and 6

Multiply x and 1

The x just gets copied along.

The answer is x

x

6*x evaluates to 6x

x+4 evaluates to x+4

Multiply 2 by x+4

we multiply 2 by each term in x+4 term by term.

This is the distributive property of multiplication.

Multiply 2 and x

Multiply 1 and x

The x just gets copied along.

x

2 × x = 2x

Multiply 2 and 4

1

2 × 4 = 8

2*(x+4) evaluates to 2x+8

6x + 2x = 8x

The answer is 8x+8

6*x+2*(x+4) evaluates to 8x+8

So, all-in-all, the left hand side of your inequality can be written as: 8x+8

Now, let's work on the right hand side of your inequality, the 2x+20

Multiply x and 2

Multiply x and 1

The x just gets copied along.

The answer is x

x

2*x evaluates to 2x

2*x+20 evaluates to 2x+20

The right hand side of your inequality can be written as: 2x+20

So with these (any) simplifications, the inequality we'll set out to solve is:

8x+8 ‹ 2x+20

Move the 8 to the right hand side by subtracting 8 from both sides, like this:

From the left hand side:

8 - 8 = 0

The answer is 8x

From the right hand side:

20 - 8 = 12

The answer is 12+2x

Now, the inequality reads:

8x ‹ 12+2x

Move the 2x to the left hand side by subtracting 2x from both sides, like this:

From the left hand side:

8x - 2x = 6x

The answer is 6x

From the right hand side:

2x - 2x = 0

The answer is 12

Now, the inequality reads:

6x ‹ 12

To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)

around the x on the left side of the inequality.

The last step is to divide both sides of the inequality by 6 like this:

To divide x by 1

The x just gets copied along in the numerator.

The answer is x

6x ÷ 6 = x

12 ÷ 6 = 2

The solution to your inequality is:

x ‹ 2

So, your solution is:

x must be less than 2

User Anton Tcholakov
by
6.7k points
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