Question

What is the value of g^-1(9)

Answer 1

g(x) = 6x - 3

Let g(x) = y:

y = 6x - 3

Make x the subject:

y = 6x - 3

6x = y + 3

`x = (y + 3)/(6)`

Replace y with x:

`g^(-1)(x) = (x + 3)/(6)`

Find g⁻¹(9):

`g^(-1)(x) = \cfrac{x + 3}{6}`

`g^(-1)(9) = \cfrac{9 + 3}{6}`

`g^(-1)(9) = 2`

Answer: 2

Answer 2

Hi there!

• g(x) = 6x - 3

Then,
if g(x) = y :-

y = 6x - 3

⇒6x = y + 3

⇒x =
`\frac{\text{y} + 3}{6}`

According to th' question :-

g⁻¹(x) =
`\frac{\text{x} + 3}{6}`

g⁻¹(9) =
`(9 + 3)/(6)`

g⁻¹(9) =
`(12)/(6)`

g⁻¹(9) = 2

Hence,
The required answer is g⁻¹(9) = 2

~ Hope it helps!