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How many electrons are necessary to produce a charge of -0.90 c ?

2 Answers

5 votes

Final answer:

To produce a charge of -0.90 C, approximately 5.62 x 10¹⁸ electrons are required, utilizing the formula ne = Total Charge / Charge per Electron with the known charge of an electron, which is -1.602 x 10⁻¹⁹ C.

Step-by-step explanation:

To determine how many electrons are necessary to produce a charge of -0.90 C, we can use the relationship that the number of electrons (ne) is equal to the total charge divided by the charge per electron. The charge on a single electron is -1.602 x 10⁻¹⁹ coulombs (C). So the calculation would be:

ne = Total Charge / Charge per Electron = -0.90 C / (-1.602 x 10⁻¹⁹ C/e)

By performing this division, we find:

ne = 0.90 C / 1.602 x 10⁻¹⁹ C/e = 5.62 x 10¹⁸ electrons

Thus, approximately 5.62 x 10¹⁸ electrons are needed to produce a charge of -0.90 C.

User Surinder
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3 votes

One electron has a charge of -1.6* 10^-19 c

x electrons have a charge of -0.90 c


1/x = -1.6 * 10^-19 c / - 0.9 c cancel the c's. and the - signs.


1/x = 1.6 * 10^-19 / 0.9 Cross multiply

0.9 = 1.6 * 10^-19 x Divide by 1.6 * 10^-19

0.9 / 1.6 * 10^-19 = x

x = 5.625 * 10^18 electrons.

User Kanadaj
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6.9k points