It would help to have the question. But I'll guess
![\sqrt[4]{x^(\frac 3 5)}{√(x^2)} = ((x^(\frac 3 5))^(\frac 1 4)) }{ x} = x^{\frac 3{20}} x = x \sqrt[20]{x^3}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/v0kx7zn5fy9pz17rkkyzt1adqb35ik0uax.png)
2nd choice.
I forgot the explanation because I was so glad to have puzzled out the question.
The fourth root is the same as the 1/4 th power.
If we know x is positive
![√(x^2)=|x|=x](https://img.qammunity.org/2019/formulas/mathematics/middle-school/vd2d4zmaz5gozdcflcz8negozfw7uss86z.png)
![\sqrt[4]{x^(\frac 3 5)}{√(x^2)}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/lxx8a17mzigef158dxsdvhd01f1csys1a0.png)
![= ((x^(\frac 3 5))^(\frac 1 4)) }{ x}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/fdnca88oszw0tstasemu9ksqgvetgcwiwj.png)
We multiply the powers:
![(a^b)^c=a^(bc)](https://img.qammunity.org/2019/formulas/mathematics/high-school/whql8m9wdxs671zw9kgct5dqdrfsqmtwrb.png)
![= x^{\frac 3{20}} x](https://img.qammunity.org/2019/formulas/mathematics/middle-school/4xg333qvmzwfv11hm83ty23lw1xe26qwx8.png)
The one-twentieth power is the twentieth root. We bring the additional factor of x to the front.
![= x \sqrt[20]{x^3}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/v3hm1czoucizalddgwb78xkmnamyzasutv.png)