So we are given the formula:
![(1)/([NO_(2)])= (kt+1)/([NO_(2)]_(0))](https://img.qammunity.org/2019/formulas/chemistry/middle-school/lzvxh6gbjfzmxzeenx6451paogyofcin7h.png)
Assuming that 'kt + 1' is one term, since it wasn't too clear in the question.
Then we multiply
on both sides to cancel out the right side, and bring it to the numerator on the left side:
![([NO_(2)]_(0))/([NO_(2)]) =kt+1](https://img.qammunity.org/2019/formulas/chemistry/middle-school/wgh9zfaeibfjsrqq09u1tpxpqog2wjwubz.png)
And now we multiply
to both sides to cancel out the left side, and bring it to the numerator essentially on the right side:
![[NO_(2)]_(0)=(kt+1)[NO_(2)]](https://img.qammunity.org/2019/formulas/chemistry/middle-school/1iu9zrau8f8t7acxexknugpn447jrx7is4.png)
And now we have the equation solved for
.