I'm going to assume that you meant the equation to be:
![h(x)=-5x-10](https://img.qammunity.org/2019/formulas/mathematics/middle-school/jnmmok50vfoseg3tgyb8qatqapwyoph79s.png)
So we're going to take that equation and we're going to solve for h(-2).
This means that we plug in a '-2' for every x in the equation:
![h(-2)=-5x-10](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2fvl5ulg6zw5duijyr8xj7ri889obe3dgd.png)
![h(-2)=-5(-2)-10](https://img.qammunity.org/2019/formulas/mathematics/middle-school/jvzk6jo284am7a0tsbruw7vo3woz90ct8j.png)
![h(-2)=10-10](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ief6trdq5kzmrt5i61ri7z9gij3zrs63ti.png)
![h(-2)=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zv7xwexyioitq2pewiio6gjg2r8ulh7i3m.png)
So when we solve the equation for h(-2), we get 0 as our answer.