Question

Please help Graph y = 1 - x 2 and y = e -x on the same set of coordinate axes. Use the graph to find the positive solution of the equation 1 - x 2 = e -x to the nearest tenth.

Answer 1

It's important to use proper symbols here in presenting math problems.

y = 1 - x 2 and y = e -x

should be written as: y = 1 - x^2 and y = e^( -x), so that there is no doubt regarding which exponent you mean.

To help y ou get started:

y = 1 - x^2

has a parabolic graph with vertex/ maximum at (0,1),

and y = e^( -x) has the graph of a decaying exponential; its y-intercept is (0,1). This graph appears primarily in Quadrant I, but also in Quadrant II, but never in Q III or Q IV.