Question

Solve by quadratic formula. x squared plus x plus 1 = 0

Answer 1

Remember that the quadratic formula is:
`(-b \pm √(b^2 - 4ac))/(2a)`.

`a` stands for the coefficient of the first term, the one associated with the
`x^2`,
`b` stands for the coefficient of the second term, the one associated with
`x`, and
`c` stands for the value of the constant.

In
`x^2 + x + 1 = 0`, our a-value is 1, our b-value is also 1, and our c-value is also 1.

Thus, when we plug in our values into our formula, we get the answer:

`(-1 \pm √(1^2 - 4(1)(1)))/(2(1)) = (-1 \pm √(-3))/(2)`

Simplifying this answer using
`i = √(-1)`, we get our final answer of:

`\boxed{x = (-1 \pm i√(3))/(2)}`