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The sum of a positive integer, x, and its inverse is 4/3 find the integer.

User Jacquel
by
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2 Answers

4 votes

Let x represent the integer.


Then x + 1/x = 4/3. Find x.


Multiply all 3 terms by 3x to clear the fractions:


3x^2 + 3 = 12x/3


3x^2 - 4x + 3 = 0


Apply the quadratic formula: a=3, b= -4, c = 3.


Then

4 plus or minus sqrt(16-4(3)(3))

x = -----------------------------------------------

6


4 plus or minus sqrt(-20)

= --------------------------------------

6


Unfortunately, these roots are not integer; worst yet, they are complex.



User Shamm
by
8.0k points
1 vote

Answer:

x = 1/3

Explanation:

Given : The sum of a positive integer, x, and its inverse is 4/3 .

To find : find the integer.

Solution : We have given The sum of a positive integer, x, and its inverse is 4/3 .

Positive number = x

Inverse of positive number x is =
(1)/(x).

According to question :


x +(1)/(x) =
(4)/(3).

On multiplication both sides by x

x² + 1 =
(4x)/(3).

On multiplying both sides by 3

3x² + 1 = 4x .

3x²- 4x + 1 = 0.

On factoring

3x²-3x -x + 1 = 0.

3x (x -1) -1 (x-1) = 0

On grouping

(3x -1)( x-1) = 0

3x - 1 = 0

x = 1/3

x -1 = 0 .

x = 1.

Therefore, x = 1/3

User Mauro Rocco
by
7.5k points

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