Question

I need help pls on math

Answer 1

`x^2-x-12=x^2+3x-4x-12=x(x+3)-4(x+3)=(x+3)(x-4)\\\\x^2-2x-8=x^2+2x-4x-8=x(x+2)-4(x+2)=(x+2)(x-4)\\\\4x^2=2x\cdot2x`

`(x^2-x-12)/(2x):(x^2-2x-8)/(4x^2)=(x^2-x-12)/(2x)\cdot(4x^2)/(x^2-2x-8)\\\\=((x+3)(x-4))/(2x)\cdot(2x\cdot2x)/((x+2)(x-4))=((x+3))/(1)\cdot(2x)/((x+2))\\\\=\boxed{(2x^2+6x)/(x+2)}`