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F(x) =x^3-2x^2-15+36

F(x) =x^3-2x^2-15+36-example-1
User Ophelia
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From the rational roots theorem we can have ±1, ±2, ±3, ±4, ±6, ±9, ±12, ±18, or ±36 as factors to this trinomial.


After checking for one factor we find that 3 works.


From long division we divide the trinomial by (x-3) since it's a factor to get:


x^2 + x -12


We can easily factor this to (x+4)(x-3)


We add in our factor we found earlier to find the factored version to be


(x-3)(x-3)(x+4)


x =3 and x = -4 are solutions to the trinomial.

User Petemoloy
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