The answer is the first option, which is:
cubic inches.
The explanation for this answer is shown below.
1. You must apply the formula for calculate the volume of a cylinder and the formula for calculate the volume of a sphere and substitute the values which are given in the problem above, as following:
![Vc=\pi r^(2) h](https://img.qammunity.org/2019/formulas/mathematics/middle-school/qf5rvr038ptse9h4cs2u9tety23d72hpqo.png)
Where
is the heigth of the cylinder and
is the radius.
![Vc=(3.14)(2in)^(2) (4in)=50.24in^(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9iwpm0srkfb9jfewkvu2rpsn09uucwn2ez.png)
![Vs=(4)/(3)r^(3) \pi](https://img.qammunity.org/2019/formulas/mathematics/middle-school/e83onubb51grjelupzw2h312wws99mcm8j.png)
Where
is the radius of the sphere.
![Vs=(4(3.14)(2in)^(3))/(3) =33.49in^(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/iy9wwgfn3knq1ucvitr69aerhbsc1yez84.png)
2. Then, you must susbtract both volumes to calculate the difference asked in the problem:
![V=50.24in^(3) -33.49in^(3) =16.75in^(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/vka1se44qrnqg68j8gahmxx2v57hpsekrr.png)
3. Therefore, the answer is the option mentioned above.