Question

A 12 kg box of kittens is pushed horizontally across the tiled floor where the coefficient of kinetic friction is 0.34. Of the push is a constant 50 N, what is the acceleration of the box

Answer 1

Step-by-step explanation:

static friction = 0.34

Acting force = 50N

mass = 12 kg

g = 9.81

a = acceleration after box moves against friction.

Acting force - Frictional Force = m * a

Frictional Force = mu*Normal

Normal = m * g

Normal = 12 * 9.81 = 117.72

Frictional Force = Normal * 0.34

Frictional Force = 117.72 * 0,34

Frictional Force = 40.02

50 - 40.02 = 12 *a

9.98 = 12*a

a = 0.8317 m/s^2