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4 votes
Hi!

Can you help me with solving this problem?

log_(8)2 + log_(8)4x^(2) = 1

Thank you so much!

1 Answer

3 votes

log_8(2) + log_8(4x^2) = 1


(adding logs of the same base is multiplying the insides of each of the logs)

log_8(8x^2) = 1


(the base raised to the exponent is equal to the inside of the logarithm)


8^1 = 8x^2


8 = 8x^2


1 = x^2


x = -1; x = 1

User Roshin Raphel
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