Answer:
Option B.
Explanation:
The given function is
![f(x)=2((2)/(3))^(x)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/8mt17gq2xs1456yet7ol6gm5252do490au.png)
From the given table we can say when we increase x by 1 (from 0 to 1) value of function is
![2((3)/(2))^(0)=2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/fr3f1sy1uzh7mv8i8ydk1vk7itwcwslqy2.png)
Now we increase x by 1 (from 1 to 2) then value of the function will be
![f(x)=2((3)/(2))^(1)=3](https://img.qammunity.org/2019/formulas/mathematics/middle-school/8x9f7keyjj7zwuayufdasdr9nchhet42iq.png)
Therefore we see the common ratio of the function value is 3/2 = 1.5
Similarly for the other values of x = 2, 3 we find he value of the function = 4.5, 6.75
Which shows the common ratio as 1.5 for every value of the function.
So we conclude with the increase of x function increases by at a constant multiplicative rate.
Option B is the answer.