Question

If it requires 37.5 mL of a 0.245 M HBr solution to neutralize 18.0 mL Mg(OH)2, what is the concentration of the Mg(OH) 2 solution?

2 HBr + Mg(OH) 2 Mg(Br) 2 + 2 H2O <- - heres the equation
0.0120 M
0.510 M
0.118 M
0.255 M

Answer 1

M1V1 = M2V2

37.5 mL * 0.245M = 18.0 mL * x M

(37.5*0.245)/18 = x M

x = 0.510

0.510 M is the answer.