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Help please!!!!!!!!!

Help please!!!!!!!!!-example-1
User Carl Poole
by
8.1k points

1 Answer

1 vote

we know that

watching the graph

the x-coordinate of the vertex is 0.5

the y-coordinate of the vertex is < -1

the axis of symmetry is the coordinate x of the vertex

so

x=0.5

the only options with those three answers is the option B and option D


check option B

vertex (0.5,-1.25)

f(x)=x²-x-1

find the value of f(x) for x=0.5 and compare with the y-coordinate of the vertex

f(0.5)=0.5²-0.5-1-------> f(0.5)=0.25-0.5-1----> f(0.5)=-1.25

-1.25 is equal to -1.25-----------> this is the function


check option D

vertex (0.5,-1.25)

find the value of f(x) for x=0.5 and compare with the y-coordinate of the vertex

f(x)=x²+x-1

f(0.5)=0.5²+0.5-1-------> f(x)=-0.25

-0.25 is not equal to -1.25-----------> Is not the function


therefore


the answer is the option B

User Launa
by
9.0k points

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