Question

Can come help me set up these problems. There two different problems.

Answer 1

Question 4:

Call the number of pennies
`p` and the number of nickles
`n`. We know that:

`p+n=199`

and

`0.01p+0.05n=7.67`

Therefore, by substitution:

`p=199-n`

`0.01(199-n)+0.05n=7.67`

`1.99-0.01n+0.05n=7.67`

`0.04n=5.68`

`n=142`

`p=199-142=57`

There are 142 nickles and 57 pennies.

Question 5

`x+y=157`

`x-y=19`

`x=157-y`

`157-y-y=19`

`157-2y=19`

`2y=138`

`y=(138)/(2)`

`y=69`

`x=157-y`

`x=157-69=88`

The numbers are 69 and 88.