Triangle ABC is dilated by a scale factor of 0.5 with the origin as the center of dilation, resulting in the image triangle A'B'C'. If A=(2,2), b=(4,3), and C=(6,…

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asked Aug 15, 2019 164k views

2 Answers

Dvdgsng · Answer 1 · 2019-08-17T09:32:11+0000

Length of BC = sqrt( (6-4)^2 + (3-3)^2) = sqrt 4 = 2

So as the factor of dilation is 0.5 the length of B'C' = 0.5*2 = 1 (answer)

Puma · Answer 2 · 2019-08-21T06:14:55+0000

Answer: 1 units

Explanation:

Given : Triangle ABC is dilated with the origin as the center of dilation, resulting in the image triangle A'B'C'.

The scale factor dilation (k) = 0.5

To find the length of
$\overline{B'C'}$ , first we need to calculate the distance from B to C or
$\overline{BC}$

If B=(4,3), and C=(6,3), then , by using distance formula

BC=√((3-3)^2+(6-4)^2)=√(0^2+2^2)=√(4)=2

Now, the length of B'C' =
k*2=0.5*2=1 units

Hence, the length of B'C' = 1 units