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Prove conjugate (z1*z2)=conjugate z1 * conjugate z2

User WiatroBosy
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1 Answer

1 vote

If
z_1 = a+bi and
z_2=c+di, then


z_1 z_2 = (a+bi)(c+di) = ac+adi+bci+bdi^2 = (ac-bd)+(ad+bc)i

So
\overline{z_1 z_2} = (ac-bd) - (ad+bc)i.

Next, compute
\overline{z_1} \cdot \overline{z_2}.


\overline{z_1} \cdot \overline{z_2} = (a-bi)(c-di)


= ac-adi-bci+bdi^2 = (ac-bd) -(ad+bc)i


User Ababak
by
4.5k points
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