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The area of a right angle is 50. One of its angles is 45 degrees. Find the lengths of the sides and hypotenuse of the triangle.

1 Answer

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It's isosceles triangle (look at the picture).

The area of the this triangle:
A=(a^2)/(2)

We have
A=50

Substitute:


(a^2)/(2)=50\ \ \ |\cdot2\\\\a^2=100\to a=√(100)\to a=10

Use the Pythagorean theorem:


b^2=a^2+a^2\\\\b^2=100+100\\\\b^2=200\to b=√(200)\\\\b=√(100\cdot2)\\\\b=√(100)\cdot\sqrt2\\\\b=10\sqrt2

Answer: 10, 10, 10√2

The area of a right angle is 50. One of its angles is 45 degrees. Find the lengths-example-1
User Stefan Mitic
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