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How much less than 3x^2−7x+9 is 2x^2+4x−8 ? Thanks!!
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How much less than 3x^2−7x+9 is 2x^2+4x−8 ?
Thanks!!

User AndreyICE
by
6.3k points

1 Answer

5 votes
Simplify.
3x^2−7x+9 - 2x^2+4x−8

1. 3x^2-2x^2 = x
2. -7x + 4x = -3x
3. 9 - 8 = 1

Combine.
x -3x +1

Thus, 2x^2+4x−8 is x -3x +1 less than 3x^2−7x+9
User Ove S
by
6.6k points
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