To find AC we need to find EC. We do this by using the Pythagorean Theorem to find a side with one side 7 and the hypotenuse root 130:


First, we single out the variable we want (C). Then, we plug in the numbers. We find that length EC is 9 inches. Therefore, AC is 24 + 9 = 33 inches.
To find AD, we must use the Pythagorean Theorem. Since this shape is symmetrical, we know that EB = ED, so ED = 7 in. Now we just need to find the hypotenuse:

First, we plug in the legs of the triangle, and then simplify. Therefore, the length AD is 25 inches.
Since this shape is a kite, ED and EB are congruent. Therefore, ED is 7 inches.