Try this solution (note, this is not the only way):
Q1: if sin(x- 3pi/2)=-sin(3pi/2- x)=--cosx=cosx, then sin(x- 3pi/2)=cosx and sin(x- 3pi/2)=7/25.
Q2: if tan(x)=√3 and x∈(180°;270°), then x=arctan√3+180°=60+180=240°.
If x=240°, then sin(x-210°)=sin30°=0.5.