Question

How do you factor for 8x^2-18x=0

Answer 1

`8x^2-18x=0\\\\2x\cdot4x-2x\cdot9=0\\\\2x(4x-9)=0`

Solution:

`2x(4x-9)=0\iff2x=0\ \vee\ 4x-9=0\\\\2x=0\ \ \ |:2\\\\x=0\\\\4x-9=0\ \ \ |+9\\\\4x=9\ \ \ \ |:4\\\\x=2.25`

Answer:

`\boxed{x=0\ \text{or}\ x=2.25}`